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new.target

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The new.target meta-property lets you detect whether a function or constructor was called using the new operator. In constructors and functions invoked using the new operator, new.target returns a reference to the constructor or function that new was called upon. In normal function calls, new.target is {{jsxref("undefined")}}.

{{InteractiveExample("JavaScript Demo: new.target")}}

```js interactive-example function Foo() { if (!new.target) { throw new TypeError("calling Foo constructor without new is invalid"); } }

try { Foo(); } catch (e) { console.log(e); // Expected output: TypeError: calling Foo constructor without new is invalid }

## Syntax

```js-nolint
new.target

Value#

new.target is guaranteed to be a constructable function value or undefined.

  • In class constructors, it refers to the class that new was called upon, which may be a subclass of the current constructor, because subclasses transitively call the superclass's constructor through super().
  • In ordinary functions, if the function is constructed directly with new, new.target refers to the function itself. If the function is called without new, new.target is {{jsxref("undefined")}}. Functions can be used as the base class for extends, in which case new.target may refer to the subclass.
  • If a constructor (class or function) is called via {{jsxref("Reflect.construct()")}}, then new.target refers to the value passed as newTarget (which defaults to target).
  • In arrow functions, new.target is inherited from the surrounding scope. If the arrow function is not defined within another class or function which has a new.target {{Glossary("binding")}}, then a syntax error is thrown.
  • In static initialization blocks, new.target is {{jsxref("undefined")}}.

Description#

The new.target syntax consists of the keyword new, a dot, and the identifier target. Because new is a reserved word, not an identifier, this is not a property accessor, but a special expression syntax.

The new.target meta-property is available in all function/class bodies; using new.target outside of functions or classes is a syntax error.

Examples#

new.target in function calls#

In normal function calls (as opposed to constructor function calls), new.target is {{jsxref("undefined")}}. This lets you detect whether a function was called with new as a constructor.

function Foo() {
  if (!new.target) {
    throw new Error("Foo() must be called with new");
  }
  console.log("Foo instantiated with new");
}

new Foo(); // Logs "Foo instantiated with new"
Foo(); // Throws "Foo() must be called with new"

new.target in constructors#

In class constructors, new.target refers to the constructor that was directly invoked by new. This is also the case if the constructor is in a parent class and was delegated from a child constructor. new.target points to the class that new was called upon. For example, when b was initialized using new B(), the name of B was printed; and similarly, in case of a, the name of class A was printed.

class A {
  constructor() {
    console.log(new.target.name);
  }
}

class B extends A {
  constructor() {
    super();
  }
}

const a = new A(); // Logs "A"
const b = new B(); // Logs "B"

new.target using Reflect.construct()#

Before {{jsxref("Reflect.construct()")}} or classes, it was common to implement inheritance by passing the value of this, and letting the base constructor mutate it.

```js example-bad function Base() { this.name = "Base"; }

function Extended() { // Only way to make the Base() constructor work on the existing // this value instead of a new object that new creates. Base.call(this); this.otherProperty = "Extended"; }

Object.setPrototypeOf(Extended.prototype, Base.prototype); Object.setPrototypeOf(Extended, Base);

console.log(new Extended()); // Extended { name: 'Base', otherProperty: 'Extended' }

However, {{jsxref("Function/call", "call()")}} and {{jsxref("Function/apply", "apply()")}} actually _call_ the function instead of _constructing_ it, so `new.target` has value `undefined`. This means that if `Base()` checks whether it's constructed with `new`, an error will be thrown, or it may behave in other unexpected ways. For example, you can't extend [`Map`](/en-US/docs/Web/JavaScript/Reference/Global_Objects/Map/Map) this way, because the `Map()` constructor cannot be called without `new`.

All built-in constructors directly construct the entire prototype chain of the new instance by reading `new.target.prototype`. So to make sure that (1) `Base` is constructed with `new`, and (2) `new.target` points to the subclass instead of `Base` itself, we need to use {{jsxref("Reflect.construct()")}}.

```js
function BetterMap(entries) {
  // Call the base class constructor, but setting `new.target` to the subclass,
  // so that the instance created has the correct prototype chain.
  return Reflect.construct(Map, [entries], BetterMap);
}

BetterMap.prototype.upsert = function (key, actions) {
  if (this.has(key)) {
    this.set(key, actions.update(this.get(key)));
  } else {
    this.set(key, actions.insert());
  }
};

Object.setPrototypeOf(BetterMap.prototype, Map.prototype);
Object.setPrototypeOf(BetterMap, Map);

const map = new BetterMap([["a", 1]]);
map.upsert("a", {
  update: (value) => value + 1,
  insert: () => 1,
});
console.log(map.get("a")); // 2

[!NOTE] In fact, due to the lack of Reflect.construct(), it is not possible to properly subclass built-ins (like Error subclassing) when transpiling to pre-ES6 code.

However, if you are writing ES6 code, prefer using classes and extends instead, as it's more readable and less error-prone.

class BetterMap extends Map {
  // The constructor is omitted because it's just the default one

  upsert(key, actions) {
    if (this.has(key)) {
      this.set(key, actions.update(this.get(key)));
    } else {
      this.set(key, actions.insert());
    }
  }
}

const map = new BetterMap([["a", 1]]);
map.upsert("a", {
  update: (value) => value + 1,
  insert: () => 1,
});
console.log(map.get("a")); // 2

Specifications#

{{Specifications}}

Browser compatibility#

{{Compat}}

See also#