TypeError: cannot use 'in' operator to search for 'x' in 'y'

The JavaScript exception "right-hand side of 'in' should be an object" occurs when the in operator was used to search in strings, or in numbers, or other primitive types. It can only be used to check if a property is in an object.

Message#

TypeError: Cannot use 'in' operator to search for 'x' in 'y' (V8-based & Firefox)
TypeError: right-hand side of 'in' should be an object, got null (Firefox)
TypeError: "y" is not an Object. (evaluating '"x" in "y"') (Safari)

Error type#

{{jsxref("TypeError")}}

What went wrong?#

The in operator can only be used to check if a property is in an object. You can't search in strings, or in numbers, or other primitive types.

Examples#

Searching in strings#

Unlike in other programming languages (e.g., Python), you can't search in strings using the in operator.

```js example-bad "Hello" in "Hello World"; // TypeError: cannot use 'in' operator to search for 'Hello' in 'Hello World'

Instead you will need to use {{jsxref("String.prototype.includes()")}}, for example.

```js example-good
"Hello World".includes("Hello");
// true

The operand can't be null or undefined#

Make sure the object you are inspecting isn't actually null or {{jsxref("undefined")}}.

```js example-bad const foo = null; "bar" in foo; // TypeError: cannot use 'in' operator to search for 'bar' in 'foo' (Chrome) // TypeError: right-hand side of 'in' should be an object, got null (Firefox)

The `in` operator always expects an object.

```js example-good
const foo = { baz: "bar" };
"bar" in foo; // false

"PI" in Math; // true
"pi" in Math; // false

Searching in arrays#

Be careful when using the in operator to search in {{jsxref("Array")}} objects. The in operator checks the index number, not the value at that index.

const trees = ["redwood", "bay", "cedar", "oak", "maple"];
3 in trees; // true
"oak" in trees; // false

See also#

• in