Temporal.Duration.prototype.add()
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The add() method of {{jsxref("Temporal.Duration")}} instances returns a new Temporal.Duration object with the sum of this duration and a given duration. The result is balanced.
Syntax#
add(other)
Parameters#
other- : A string, an object, or a {{jsxref("Temporal.Duration")}} instance representing a duration to add to this duration. It is converted to a
Temporal.Durationobject using the same algorithm as {{jsxref("Temporal/Duration/from", "Temporal.Duration.from()")}}.
Return value#
A new Temporal.Duration object representing the sum of this duration and other.
Exceptions#
- {{jsxref("RangeError")}}
- : Thrown in one of the following cases:
- Either
thisorotheris a calendar duration (it has a non-zeroyears,months, orweeks), because calendar durations are ambiguous without a calendar and time reference. - The sum of
thisandotheroverflows the maximum or underflows the minimum representable duration, which is ±253 seconds.
- Either
Description#
Non-calendar durations unambiguously represent a fixed amount of time. Internally, this and other are both converted to nanoseconds (assuming 24-hour days) and added together. The result is then converted back to a Temporal.Duration object, so the result is always balanced or top-heavy with the largest possible unit being days.
If you want to perform addition or subtraction with a calendar duration, you can add both durations to a starting point and then figure out the difference between the two resulting instants; that is, dur1 + dur2 is equivalent to (start + dur1 + dur2) - start.
To add a duration to a date or time, use the add() method of the date or time object instead.
Examples#
Using add()#
const d1 = Temporal.Duration.from({ hours: 1, minutes: 30 });
const d2 = Temporal.Duration.from({ hours: -1, minutes: -20 });
const d3 = d1.add(d2);
console.log(d3.toString()); // "PT10M"
Adding calendar durations#
const d1 = Temporal.Duration.from({ days: 1 });
const d2 = Temporal.Duration.from({ months: 1 });
d1.add(d2); // RangeError: for calendar duration arithmetic, use date arithmetic relative to a starting point
const start = Temporal.PlainDateTime.from("2022-01-01T00:00"); // ISO 8601 calendar
const result = start.add(d1).add(d2).since(start);
console.log(result.toString()); // "P32D"
Specifications#
{{Specifications}}
Browser compatibility#
{{Compat}}
See also#
- {{jsxref("Temporal.Duration")}}
- {{jsxref("Temporal/Duration/subtract", "Temporal.Duration.prototype.subtract()")}}