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String.prototype.endsWith()

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The endsWith() method of {{jsxref("String")}} values determines whether a string ends with the characters of this string, returning true or false as appropriate.

{{InteractiveExample("JavaScript Demo: String.prototype.endsWith()")}}

```js interactive-example const str1 = "Cats are the best!";

console.log(str1.endsWith("best!")); // Expected output: true

console.log(str1.endsWith("best", 17)); // Expected output: true

const str2 = "Is this a question?";

console.log(str2.endsWith("question")); // Expected output: false

## Syntax

```js-nolint
endsWith(searchString)
endsWith(searchString, endPosition)

Parameters#

  • searchString
  • : The characters to be searched for at the end of str. Cannot be a regex. All values that are not regexes are coerced to strings, so omitting it or passing undefined causes endsWith() to search for the string "undefined", which is rarely what you want.
  • endPosition {{optional_inline}}
  • : The end position at which searchString is expected to be found (the index of searchString's last character plus 1). Defaults to str.length.

Return value#

true if the given characters are found at the end of the string, including when searchString is an empty string; otherwise, false.

Exceptions#

  • {{jsxref("TypeError")}}
  • : Thrown if searchString is a regex.

Description#

This method lets you determine whether or not a string ends with another string. This method is case-sensitive.

Examples#

Using endsWith()#

const str = "To be, or not to be, that is the question.";

console.log(str.endsWith("question.")); // true
console.log(str.endsWith("to be")); // false
console.log(str.endsWith("to be", 19)); // true

Specifications#

{{Specifications}}

Browser compatibility#

{{Compat}}

See also#